Determine the amount of energy,in joules,stored in a defibrillator 17.0- F capacitor that has a potential difference of 9.25 V
Answer (1)
Answer:Energy (E) = 0.5 x Capacitance (C) x Voltage^2 (V^2)Dito, C = 17.0 F at V = 9.25 VKaya, E = 0.5 x 17.0 F x (9.25 V)^2E = 0.5 x 17.0 x 85.5625E = 726.5625 JAng sagot ay: 727 Joules
