A ball is thrown vertically upwards with an initial velocity of 15 m/s. calculate the maximum height reached by the ball.
(Assume g=9.8m/s²)

The maximum height is approximately 11.48 meters.[tex]________________________________[/tex]To calculate the maximum height reached by a ball thrown vertically upward, we can use the kinematic equation:[tex]\[v^2 = u^2 - 2gh\][/tex]Where: [tex]\( v = 0 \, \text{m/s} \)[/tex] at the maximum height (final velocity) [tex]\( u = 15 \, \text{m/s} \)[/tex] (initial velocity) [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex] (acceleration due to gravity) [tex]\( h \)[/tex] is the maximum height Plug the values into the formula:[tex]\[0 = (15)^2 - 2(9.8)h\][/tex][tex]\[0 = 225 - 19.6h\][/tex][tex]\[19.6h = 225\][/tex][tex]\[h = \frac{225}{19.6} \approx 11.48 \, \text{m}\][/tex]Answer: The maximum height is approximately 11.48 meters.

Answered by Nikovax | 2025-04-05