Scar starts from rest and accelerates uniformly at 3.85 m/s over a time of 55.35 seconds. Determine the acceleration and the distance travelled

Answer:The problem already states that the acceleration is uniform at 3.85 m/s². Therefore, the acceleration is 3.85 m/s^2. To determine the distance traveled, we can use the following equation of motion: s = ut + (1/2)at² Where: - s = distance traveled - u = initial velocity (0 m/s since Scar starts from rest) - a = acceleration (3.85 m/s²) - t = time (55.35 s) Plugging in the values: s = (0 m/s)(55.35 s) + (1/2)(3.85 m/s²)(55.35 s)²s = 0 + (1/2)(3.85 m/s²)(3062.3225 s²)s ≈ 5897.7 m Therefore, the distance traveled is approximately 5897.7 meters

Answered by hiakaliel | 2025-04-04