a cannon fires a shell at 80m/s at 37°.find the horizontal range
Answer (1)
The horizontal range of a shell fired from a cannon is 629.5 meters.Th formula for finding the horizontal range of a projectile isR = [tex]v_{o} ^{2}[/tex] sin(2Θ) ÷ gWhere[tex]v_{o}[/tex] = initial velocity (80m/s)Θ = angle of projection (37°)g = acceleration due to gravity (the fixed value is 9.81 m/s²)R =[ [tex]v_{o} ^{2}[/tex] sin(2Θ)] ÷ gR= [ [tex]80 ^{2}[/tex] sin(2 × 37°)] ÷ 9.81R= [6400 sin(2 × 37°)] ÷ 9.81R= (6400 × 0.9659) ÷ 9.81R= 6178.56 ÷ 9.81R≈ 629.5 meters
