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Answer:Question: The image shows a diagram of a person skateboarding down a ramp. The question asks to determine the potential energy (PE), kinetic energy (KE), mechanical energy (ME), velocity (V), and height (h) of the skateboarder. The image lacks crucial information such as mass, velocity, height, and the angle of the ramp. To provide a solution, I will make reasonable assumptions. Assumptions: - Mass (m): I assume the mass of the skateboarder and skateboard is 50 kg. - Height (h): I assume the initial height (h) of the skateboarder at the top of the ramp is 2 meters. - Velocity (V): I assume the skateboarder starts from rest at the top of the ramp, so the initial velocity is 0 m/s. The final velocity at the bottom of the ramp will be calculated. - Ramp Angle: I assume the ramp is frictionless and at a 30-degree angle to the horizontal. This simplifies the calculation; a real-world scenario would involve friction. - Acceleration due to gravity (g): I assume g = 9.8 m/s². Solution Process: 1. Potential Energy (PE): PE = mgh, where m is mass, g is acceleration due to gravity, and h is height. - PE = (50 kg)(9.8 m/s²)(2 m) = 980 J 2. Kinetic Energy (KE): KE = 1/2mv², where m is mass and v is velocity. Since the skateboarder starts from rest, the initial KE is 0 J. At the bottom of the ramp, we can find the final velocity using conservation of energy. 3. Conservation of Energy: The total mechanical energy (ME) remains constant if we assume no energy loss dQuestion: The image shows a diagram of a person skateboarding down a ramp. The question asks to determine the potential energy (PE), kinetic energy (KE), mechanical energy (ME), velocity (V), and height (h) of the skateboarder. The image lacks crucial information such as mass, velocity, height, and the angle of the ramp. To provide a solution, I will make reasonable assumptions. Assumptions: - Mass (m): I assume the mass of the skateboarder and skateboard is 50 kg. - Height (h): I assume the initial height (h) of the skateboarder at the top of the ramp is 2 meters. - Velocity (V): I assume the skateboarder starts from rest at the top of the ramp, so the initial velocity is 0 m/s. The final velocity at the bottom of the ramp will be calculated.- Ramp Angle: I assume the ramp is frictionless and at a 30-degree angle to the horizontal. This simplifies the calculation; a real-world scenario would involve friction. - Acceleration due to gravity (g): I assume g = 9.8 m/s². Solution Process: 1. Potential Energy (PE): PE = mgh, where m is mass, g is acceleration due to gravity, and h is height. - PE = (50 kg)(9.8 m/s²)(2 m) = 980 J 2. Kinetic Energy (KE): KE = 1/2mv², where m is mass and v is velocity. Since the skateboarder starts from rest, the initial KE is 0 J. At the bottom of the ramp, we can find the final velocity using conservation of energy. 3. Conservation of Energy: The total mechanical energy (ME) remains constant if we assume no energy loss due to friction. Therefore, the initial PE is equal to the final KE at the bottom of the ramp. - Initial ME = PE = 980 J - Final ME = KE = 980 J4. Velocity (V) at the bottom of the ramp: - 980 J = 1/2(50 kg)v² - v² = 39.2 m²/s² - v = √39.2 m²/s² ≈ 6.26 m/s 5. Mechanical Energy (ME): ME = PE + KE. Since energy is conserved (ignoring friction), ME remains constant throughout the motion. - ME = 980 J (at the top and bottom of the ramp) Answer: - PE = 980 J - KE = 980 J (at the bottom of the ramp) - ME = 980 J - V = 6.26 m/s (approximately, at the bottom of the ramp) - h = 2 m Key Concepts/Tips: - Potential Energy: Energy stored due to an object's position or configuration. - Kinetic Energy: Energy of motion. - Mechanical Energy: The sum of potential and kinetic energy.- Conservation of Energy: In an ideal system (no friction or energy loss), the total mechanical energy remains constant. This principle was used to calculate the final velocity at the bottom of the ramp. In a real-world scenario, friction would reduce the final velocity and mechanical energy.
