A sports car starts from rest and accelerates at 4.2 m/s² for 15 seconds before reaching its topspeed. How far does the car travel during this time? Give the formula
Answer (2)
Answer:ang kuwentong bina sa ay ang aking minamahal
Answer:To solve this, we use the kinematic equation:d = v₀t + 0.5at²Where:- d is the distance traveled.- v₀ is the initial velocity (in this case, 0 m/s since the car starts from rest).- t is the time (15 seconds).- a is the acceleration (4.2 m/s²).Substitute the values into the formula:d = (0)(15) + 0.5(4.2)(15²) d = 0 + 0.5(4.2)(225)d = 0.5 × 4.2 × 225d = 472.5 metersSo, the car travels 472.5 meters during this time.
