A ball launched horizontally from balcony 0.85 m above the ground with a initial velocity of 1.2 m/s, how long does it takes for the ball to hit the ground and what is the final velocity of the ball just before it hits the ground?
Answer (1)
d=(1/2)gt²0.85m=(1/2)(9.8m/s²)t²t=√(2(0.85)/(9.8m/s²))t=0.42svf=vi+atvf=vivf=1.2m/s
