The acceleration of gravity on the moon is 1.62m/s2. If a ball is dropped on the moon from a height of 2.75m. determine the time for the Ball to fall to the surface of the moon
Answer (1)
Answer:We can use the following kinematic equation to solve this problem: d = v₀t + (1/2)at² Where: - d = distance (2.75 m)- v₀ = initial velocity (0 m/s, since the ball is dropped)- a = acceleration due to gravity on the moon (1.62 m/s²)- t = time (what we want to find) Substituting the known values: 2.75 m = (0 m/s)t + (1/2)(1.62 m/s²)t² Simplifying: 2.75 m = 0.81 m/s² * t² Solving for t²: t² = 2.75 m / 0.81 m/s²t² ≈ 3.395 s² Taking the square root of both sides to find t: t ≈ √3.395 s²t ≈ 1.84 s Therefore, it will take approximately 1.84 seconds for the ball to fall to the surface of the moon.
