A 30.0 N force is exerted on the small piston of a hydraulic system. The cross-sectional area of the small piston is 0.0400m². What is the magnitude of the weight that can be lifted by a large piston, which has a surface area of 0.100m²?
Answer (1)
[tex]\[P = \frac{F_1}{A_1} = \frac{30.0\,\text{N}}{0.0400\,\text{m}^2} = 750\,\text{Pa}\]\[F_2 = P \times A_2 = 750\,\text{Pa} \times 0.100\,\text{m}^2 = 75.0\,\text{N}\][/tex]
