The voltage of the metal is 1350 Volts.Given:Coulomb's constant (k) = 9 × 10⁹ N·m²/C²Electrical charge (q) = 3.0 nC = 3.0 × 10^-9 CDistance (r) = 20 mm = 0.20 mRequired: VoltageEquation:[tex]\sf V = \dfrac{kq}{r}[/tex]where,V is the voltagek is Coulomb's constantq is the electrical charger is the distance between the center of the sphereSolution:[tex]\sf V = \frac{(9 \times 10^9 \: N·m²/C²) (3.0 \times 10^{-9} \: C)}{0.020 \: m}[/tex]Answer:[tex]\sf V = 1350 \: V[/tex]