This follows the 9:3:3:1 ratio typical of a dihybrid cross.[tex]________________________________[/tex]To determine the genotypic and phenotypic ratios of the offspring from a cross between two rabbits with the genotype GgBb × GgBb, we need to consider a dihybrid cross (two genes, each with two alleles). Step 1: Define the Alleles G (Gray fur) is dominant over g (White fur) B (Black eyes) is dominant over b (Blue eyes) Each parent has the genotype GgBb, meaning they are heterozygous for both traits.Step 2: Determine Possible Gametes Each parent can pass one allele for fur color (G or g) and one allele for eye color (B or b). The possible gametes are: GB, Gb, gB, gbStep 3: Create the Punnett Square [tex]\[\begin{array}{c|cccc}& GB & Gb & gB & gb \\\hline GB & GGBB & GGBb & GgBB & GgBb \\Gb & GGBb & GGbb & GgBb & Ggbb \\gB & GgBB & GgBb & ggBB & ggBb \\gb & GgBb & Ggbb & ggBb & ggbb \\\end{array}\][/tex]Step 4: Determine Genotypic Ratio From the Punnett square, we count each unique genotype1 GGBB2 GGBb2 GgBB4 GgBb1 GGbb2 Ggbb1 ggBB2 ggBb1 ggbbSo the genotypic ratio is: 1 GGBB : 2 GGBb : 2 GgBB : 4 GgBb : 1 GGbb : 2 Ggbb : 1 ggBB : 2 ggBb : 1 ggbbStep 5: Determine Phenotypic RatioGray fur, Black eyes (G_B_) → 9 (GGBB, GGBb, GgBB, GgBb) Gray fur, Blue eyes (G_bb) → 3 (GGbb, Ggbb) White fur, Black eyes (ggB_) → 3 (ggBB, ggBb) White fur, Blue eyes (ggbb) → 1 (ggbb) Thus, the phenotypic ratio is: 9 Gray, Black : 3 Gray, Blue : 3 White, Black : 1 White, Blue*This follows the 9:3:3:1 ratio typical of a dihybrid cross.