1. A 3 kg soccer ball is kicked with a velocity of 20 m/s towards a goal. The ball is then caught by a goalkeeper, who stops it in 0.5 seconds. Calculate the change in momentum of the ball when the goalkeeper catches it.pa ans po asap thnx
Answer (1)
[tex]\begin{gathered}\begin{gathered}{\underline{\huge \mathbb{A} {\large \mathrm {NSWER : }}}} \\\end{gathered}\end{gathered}[/tex] To calculate the change in momentum of the soccer ball when the goalkeeper catches it, follow these steps: Understand the concepts Momentum (p) is defined as the product of mass and velocity. The formula for momentum is: [tex]p = m \times v[/tex] where: [tex]m[/tex] is the mass (in kilograms),[tex]v[/tex] is the velocity (in meters per second). Given information Mass of the soccer ball, [tex]m = 3 \text{ kg}[/tex] Initial velocity of the soccer ball, [tex]v_{initial} = 20 \text{ m/s}[/tex]Final velocity of the soccer ball when caught by the goalkeeper, [tex]v_{final} = 0 \text{ m/s}[/tex] (since the ball comes to a stop) Calculate the initial momentum Using the momentum formula: [tex]p_{initial} = m \times v_{initial} = 3 \text{ kg} \times 20 \text{ m/s} = 60 \text{ kg m/s}[/tex] Calculate the final momentum When the goalkeeper catches the ball, it stops, so: [tex]p_{final} = m \times v_{final} = 3 \text{ kg} \times 0 \text{ m/s} = 0 \text{ kg m/s}[/tex] Calculate the change in momentum The change in momentum ([tex]\Delta p[/tex]) is the final momentum minus the initial momentum: [tex]\Delta p = p_{final} - p_{initial} = 0 \text{ kg m/s} - 60 \text{ kg m/s} = -60 \text{ kg m/s}[/tex] Complete answer The change in momentum of the soccer ball when the goalkeeper catches it is: [tex]\Delta p = -60 \text{ kg m/s}[/tex] This negative sign indicates that the momentum has decreased, as the ball is brought to a stop.
