When temperature increases, gas particles move faster, causing the gas to expand (increase in volume).When temperature decreases, gas particles slow down, leading to a decrease in volume.Example Problem:A balloon has a volume of 2.5 L at 300 K. If the temperature increases to 600 K, what is the new volume?Solution:Using Charles's Law:₁ / ₁ = ₂ / ₂( 2.5L ) / ( 300K ) = ₂ / (600K)Cross multiply:₂ = ( 2.5 ) × ( 600 ) / ( 300 )₂ = 5.0So, the balloon doubles in size as temperature doubles!