A 7.25L sample of nitrogen gas is determined to contain 0.75 mole of nitrogen.How many moles of nitrogen gas would there be in a 20L sample provided the temperature and pressure remain the same?
Answer (1)
Answer:At 20L, there would be approximately 2.07 moles of nitrogen gas. Avogadro’s Law, which states: [tex]\frac{V_1}{n_1} = \frac{V_2}{n_2}[/tex]where: [tex]V_1 = 7.25L[/tex] (initial volume) [tex]n_1 = 0.75[/tex] moles (initial amount of nitrogen) [tex]V_2 = 20L[/tex] (final volume) [tex]n_2[/tex] = ? (final amount of nitrogen)Solve for [tex]n_2[/tex][tex]n_2 = n_1 \times \frac{V_2}{V_1}[/tex][tex]n_2 = 0.75 \times \frac{20}{7.25}[/tex][tex]n_2 = 0.75 \times 2.76[/tex][tex]n_2 \approx 2.07 \ \tt{ moles}\\[/tex]
