2. A rock was dropped on top of the building that is-122.5m high. How long will the rock hit the ground? Given d=122.5m Vi=om/s ag = -9.8m/s² t=?
Answer (1)
Answer: 4.9974 seconds or 5 secondsStep-by-step solution:[tex]d=122.5[/tex] [tex]Vi=0 m/s[/tex][tex]a=9.81m/s^2[/tex][tex]t=?[/tex]Since [tex]Vi=0[/tex], we can simplify it to:[tex]d=\frac{1}{2}at^2[/tex]Solving for [tex]t[/tex]:[tex]t^2=\frac{2d}{a}[/tex][tex]t=\sqrt{24.97}[/tex][tex]t=4.9974[/tex]≈ 5 seconds
