a car moving at 20m/s drives off a 10 meter high cliff. how far from base of the cliff will the car land? solution?
Answer (1)
Solve this problem, breaking it down into horizontal and vertical components: 1. Vertical Motion:- We need to find the time it takes for the car to fall 10 meters. We can use the following kinematic equation:• d = v₀t + (1/2)at² Where: • d = vertical distance (10 m) • v₀ = initial vertical velocity (0 m/s, since the car drives horizontally off the cliff) • a = acceleration due to gravity (approximately 9.8 m/s²) • t = time• Plugging in the values: • 10 m = 0 + (1/2)(9.8 m/s²)t² • t² = (10 m) / (4.9 m/s²) • t ≈ 1.43 s2. Horizontal Motion: - The horizontal velocity remains constant at 20 m/s. We can use the following equation: • distance = velocity × time• Plugging in the values: • distance = 20 m/s × 1.43 s ≈ 28.6 m Answer: The car will land approximately 28.6 meters from the base of the cliff.
