a ball rolls down ramp for 15 seconds. if the initial velocity of the ball was o.8 m/s and the final velocity was 7 m/s, what was the acceleration of the ball?
Answer (1)
The acceleration of the ball is 0.41 m/s² (rounded to two decimal places).Acceleration () is the rate of change of velocity over time. It tells us how much the speed of an object increases (or decreases) per unit time. The standard unit of acceleration is meters per second squared (m/s²).To solve for the acceleration () of the ball, we use the kinematic equation:[tex]a = \frac{v_{f-V_{i}} }{t} \newline\\a=\frac{7-0.8}{15} \newline\\a=0.413 m/s^2[/tex]How does acceleration work in this scenario?Since the ball rolls down the ramp, gravity causes it to speed up over time.The initial velocity means the ball already had some movement when it started.The final velocity means after 15 seconds, the ball has reached 7 m/s.The acceleration we calculated (0.41 m/s²) tells us that every second, the ball’s speed increases by 0.41 m/s.
