A 3.00L of a gas is at 740.0 mm Hg pressure.What is its volume at standard pressure?
Answer (1)
to find the standard pressure, one must use Boyle's law to solve this problem. Boyle's law is expressed as:P₁V₁ = P₂V₂We know that P₁ = 3.00L, V₁ = 740.0 mm Hg, and P₂ = 760 mm Hg (760mm, or the standard pressure, is a universal constant). We will now try to find V₂.V₂ = (P₁V₁) / P₂V₂ = (740.0 mm Hg * 3.00 L) / 760 mm HgV₂ = 2220 / 760 LV₂ ≈ 2.92 LHope it helps! =)- Sam <3
