an oxygen gas at 2.0 atm of pressure a volume of 2.0L .What is the gas if pressure is reduce to 0.5 atm. temperature and amount of oxygen are held constant
Answer (1)
Answer:To find the new volume of the gas when the pressure is reduced, you can use Boyle's Law, which states that for a given mass of gas at constant temperature, the product of pressure and volume is constant. The formula is:\[P_1 V_1 = P_2 V_2\]Where:- \( P_1 \) = initial pressure- \( V_1 \) = initial volume- \( P_2 \) = final pressure- \( V_2 \) = final volumeGiven:- \( P_1 = 2.0 \, \text{atm} \)- \( V_1 = 2.0 \, \text{L} \)- \( P_2 = 0.5 \, \text{atm} \)You can rearrange the equation to solve for \( V_2 \):\[V_2 = \frac{P_1 V_1}{P_2}\]Substituting the values:\[V_2 = \frac{2.0 \, \text{atm} \times 2.0 \, \text{L}}{0.5 \, \text{atm}} = \frac{4.0 \, \text{atm} \cdot \text{L}}{0.5 \, \text{atm}} = 8.0 \, \text{L}\]So, the new volume \( V_2 \) when the pressure is reduced to 0.5 atm is **8.0 L**.
