(Kindly help me with this? anyone I was absent during this lesson.)
Answer (1)
Answer:This problem describes a monohybrid cross in pea plants, focusing on the trait of flower position (axial vs. terminal). Here's how to solve it: 1. Set up the Punnett Square: - Parental Genotypes: Male (AA) x Female (aa)- Gametes: The male parent produces only 'A' gametes, and the female parent produces only 'a' gametes. The Punnett Square will look like this: A A a Aa Aa a Aa Aa 2. Genotypic Ratio and Percentage: All offspring have the genotype Aa. Therefore, the genotypic ratio is 100% Aa. 3. Phenotypic Ratio and Percentage: Since 'A' (axial) is dominant over 'a' (terminal), all offspring will have axial flowers. The phenotypic ratio is 100% axial. Conclusion: The cross between a homozygous axial pea plant (AA) and a homozygous terminal pea plant (aa) results in 100% heterozygous (Aa) offspring, all exhibiting the axial flower phenotype. This demonstrates Mendel's Law of Dominance.
