Constant variables Focal length = 5cm Object height = 2cm Center of curvature =10cm Distance of object = 3cm What to draw? P-F ray F-P ray V ray C ray. please help
Answer (1)
To draw the **ray diagram** for a **concave mirror** based on the given variables, follow these steps:---### Given:- **Focal length (f)** = 5 cm - **Object height (h)** = 2 cm - **Center of curvature (C)** = 10 cm (since \( C = 2f \)) - **Distance of object (u)** = 3 cm (object is placed between the mirror and the focal point)---### Steps to Draw the Ray Diagram:1. **Draw the Principal Axis** - Draw a horizontal line to represent the principal axis of the mirror.2. **Mark the Pole (P) and Focal Point (F)** - Mark the **pole (P)** at the center of the mirror. - Mark the **focal point (F)** at 5 cm from the pole (since \( f = 5 \) cm). - Mark the **center of curvature (C)** at 10 cm from the pole (since \( C = 2f \)).3. **Draw the Concave Mirror** - Draw a concave mirror (a curved line) with the pole (P) at its center.4. **Place the Object** - The object is placed at a distance of 3 cm from the pole (between the mirror and the focal point). - Draw an upright arrow of height 2 cm to represent the object.5. **Draw the Rays**: - **P-F Ray (Parallel to Principal Axis - Passes through Focal Point):** - Draw a ray from the top of the object parallel to the principal axis. - After reflection, this ray will pass through the focal point (F). - **F-P Ray (Passes through Focal Point - Reflects Parallel to Principal Axis):** - Draw a ray from the top of the object that passes through the focal point (F). - After reflection, this ray will travel parallel to the principal axis. - **V Ray (Passes through the Vertex - Reflects Symmetrically):** - Draw a ray from the top of the object that passes through the pole (P). - After reflection, this ray will reflect symmetrically (at the same angle). - **C Ray (Passes through the Center of Curvature - Reflects Back on Itself):** - Draw a ray from the top of the object that passes through the center of curvature (C). - After reflection, this ray will retrace its path back.6. **Locate the Image**: - The reflected rays will appear to diverge. Extend the reflected rays backward (using dashed lines) to find the point where they intersect. - This intersection point is the **virtual image**. - The image will be **upright**, **magnified**, and **virtual** (since the object is placed between the mirror and the focal point).---### Key Observations:- The image is formed behind the mirror. - The image is **virtual**, **upright**, and **larger** than the object. - The magnification (\( m \)) can be calculated using the formula: \[ m = \frac{v}{u} \] where \( v \) is the image distance (negative for virtual images).---If you need further clarification or a sketch, let me know!
