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Answer (2)
Answer: Number One: Point (3, -1) with a Slope of -11. Use the point-slope form of the equation of a line: y − y 1 =m(x−x1) where (x_1, y_1) is the point and m is the slope. Using the point (3, -1) and slope m = -1 : y - (-1) = -1(x - 3)y - (-1) = -1(x - 3) y + 1 = -x + 3 y = -x + 22. Convert to standard form (Ax + By = C): x + y = 2 Thus, the equation in standard form is: x + y = 2 Number Two: Point (-2, 5) with a Slope of -41. Use the point-slope form again: Using the point (-2, 5) and slope m = -4 : y - 5 = -4(x - (-2))y - 5 = -4(x - (-2)) y - 5 = -4(x + 2)y - 5 = -4(x - (-2)) y - 5 = -4(x + 2) y - 5 = -4x - 8y - 5 = -4(x - (-2)) y - 5 = -4(x + 2) y - 5 = -4x - 8 y = -4x - 3 2. Convert to standard form 4x + y = -3 To make the right side positive, multiply the entire equation by -1: -4x - y = 3 Thus, the equation in standard form is: 4x + y = -3Summary of Results:1. For point (3, -1) with slope -1: Standard Form: x + y = 22. For point (-2, 5) with slope -4: Standard Form: 4x + y = -3 Step-by-step explanation:HOPE IT HELPS
Answer:Profile Summary:A dedicated and hardworking student with a strong passion for learning and personal growth. Highly motivated, adaptable, and eager to take on new challenges, with excellent time management and problem-solving skills. Works well both independently and in a team, demonstrating strong communication and leadership abilities. Committed to academic excellence while actively participating in extracurricular activities to develop a well-rounded skill set. Always willing to learn, improve, and contribute positively to any environment.
