What is the magnitude of a vector that makes an angle of 30 to the horizontal and whose x- component is 3 units?

Answer:We can use trigonometry to solve this problem.Let's denote the magnitude of the vector as |V|.We know that: * cos(30°) = adjacent side / hypotenuse = x-component / |V| * cos(30°) = 3 / |V|Therefore, * |V| = 3 / cos(30°)Using a calculator, we find that: * |V| ≈ 3.46 unitsSo, the magnitude of the vector is approximately 3.46 units.

Answered by manilynalipala3 | 2024-10-23