1. What is the volume percent of NH4NO3 (ammonium nitrate) in a solution made byadding 45 mL of ammonium nitrate to 320 mL of water?
Answer (1)
VOLUME PERCENT[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex] Answer: 12.3%Solution: Find the total volume of the solution by adding the two given volumes. [tex] \rm V(Solution) = 45 \: ml + 320 \: ml[/tex][tex] \rm V(Solution) = 365 \: ml[/tex]Find the volume percent of ammonium nitrate in the solution using the formula. [tex] \rm V\% = \frac{ V(NH_4NO_3) }{V(Solution)} \cdot 100\% \\ [/tex][tex] \rm V\% = \frac{45}{365} \cdot 100\% \\ [/tex][tex] \rm V\% = 0.123 \cdot 100\% [/tex][tex] \rm V\% = 12.3\%[/tex]Therefore, the volume percent of ammonium nitrate is 12.3%[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex] I HOPE IT HELPS :)
