2. Two solutions of a substance (non-electrolyte) are
mixed in the following manner. 480 mL of 1.5 M first solution + 520 mL of 1.2 M second solution. What is the molarity of the final mixture?

Question

2. Two solutions of a substance (non-electrolyte) are 
mixed in the following manner. 480 mL of 1.5 M first solution + 520 mL of 1.2 M second solution. What is the molarity of the final mixture?

cyrusmendoza901 · Answer

Two solutions of a substance (non-electrolyte) are mixed in the following manner. 480 ml of 1.5 M first solution + 520 ml of 1.2 M second solution

2. Two solutions of a substance (non-electrolyte) are mixed in the following manner. 480 mL of 1.5 M first solution + 520 mL of 1.2 M second solution. What is the molarity of the final mixture?

Answer (1)

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2. Two solutions of a substance (non-electrolyte) are
mixed in the following manner. 480 mL of 1.5 M first solution + 520 mL of 1.2 M second solution. What is the molarity of the final mixture?

[Sagot para sa’yo] The mass of H₂O produced when 209 g of methanol (CH₃OH) are used up can be calculated using stoichiometry and the given balanced equation: 2 CH₃OH + 3 O₂ → 2 CO₂ + 4 H₂O