transforming quadratic Function from standard form to verter form F(+) = x²+6x-12​

Step-by-step explanation:f(x) = x² + 6x – 12a = 1, b = 6, c= –12= (x² +6x) –12[tex] \frac{b^{2} }{4a^{2} } = \frac{( {6})^{2} }{4( {1)}^{2} } = \frac{36}{4} = 9[/tex]add 9 to (x² + 6x) which turns it into a perfect square trinomial. also subtract 9 from –12= (x² + 6x + 9) – 12 – 9express x² + 6x + 9 as a squared binomial and add like constantsf(x) = (x+3)² –21 h = – 3k = – 21

Answered by Seya28382 | 2024-10-21