Answer:Let's help Emma with her purchasing decision.Let p = number of pens and n = number of notebooks.Constraints:1. Total cost: 20p + 50n ≤ 500 (Emma's budget)2. Total items: p + n ≥ 10 (Emma wants to sell at least 10 items)3. Non-negativity: p ≥ 0, n ≥ 0 (number of items cannot be negative)Inequality representation:20p + 50n ≤ 500p + n ≥ 10Graphical representation:(You can visualize the inequalities as a system of linear equations on a graph)Solutions:Some possible combinations of pens and notebooks Emma can buy:| Pens (p) | Notebooks (n) | Total Cost || --- | --- | --- || 10 | 0 | 200 || 8 | 2 | 240 || 6 | 4 | 280 || 4 | 6 | 320 || 2 | 8 | 360 || 0 | 10 | 400 |