Answer:For the first system of equations:To graph x+y=5x+y=5, we can rewrite it as y=−x+5y=−x+5. This is a line with a slope of −1−1 and a yy-intercept of 55.To graph x−y=5x−y=5, we can rewrite it as y=x−5y=x−5. This is a line with a slope of 11 and a yy-intercept of −5−5.By graphing these two lines, we can see that they intersect at the point (5,0)(5,0).For the second system of equations:To graph 2x+3y=122x+3y=12, we can rewrite it as y=−23x+4y=− 32 x+4. This is a line with a slope of −23− 32 and a yy-intercept of 44.To graph 3x+2y=63x+2y=6, we can rewrite it as y=−32x+3y=− 23 x+3. This is a line with a slope of −32− 23 and a yy-intercept of 33.By graphing these two lines, we can see that they intersect at the point (0,4)(0,4).Therefore, the solutions to the two systems of linear equations are (5,0)(5,0) and (0,4)(0,4), respectively