In a library the librarian wants to display 3 volumes of a book series. The Internal lengt of the bookshelf is 60 2/5cm.. The first book has a thickness of 2 cm what is the maximum number of books that can be displayed on the top shelf?

Answer:Here's how to solve the problem: 1. Convert the bookshelf length to a fraction: - 60 2/5 cm = (60 * 5 + 2) / 5 = 302/5 cm 2. Calculate the total space needed for one set of the book series: - Each set has 3 volumes.- One volume is 2 cm thick.- Total space needed: 3 volumes * 2 cm/volume = 6 cm 3. Divide the bookshelf length by the space needed for one set: - 302/5 cm / 6 cm/set = 50 2/5 sets 4. Determine the maximum number of books: - Since you can't display a fraction of a set, the maximum number of books is the whole number part of the result: 50 sets Therefore, the maximum number of books that can be displayed on the top shelf is 50 sets.Step-by-step explanation:pa brainliest po thanks

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