Problem 1: A spinning top has a moment of inertia of 0.02 kg-m². It is spinning at 100 revolutions per minute (rpm). What is its angular momentum? ​

To find angular momentum (L), we need:1. Moment of inertia (I) = 0.02 kg-m²2. Angular velocity (ω) in radians per second (rad/s)Convert rpm to rad/s100 rpm = 100 × (2π/60) rad/s ≈ 10.47 rad/sNow, calculate angular momentumL = I × ω= 0.02 kg-m² × 10.47 rad/s≈ 0.2094 kg-m²/sAnswer: The spinning top's angular momentum is approximately 0.21 kg-m²/s

Answered by Heartzloviii | 2024-10-23