problem on a graphing paper:1.y < 2x -12.y ≤ x + 3​

Answer:Okay, here's how to graph the inequalities y < 2x - 1 and y ≤ x + 3 on graphing paper: 1. Graphing y < 2x - 1 - Treat it as an equation: Start by graphing the line y = 2x - 1. - Find the y-intercept: When x = 0, y = -1. Plot the point (0, -1).- Find the x-intercept: When y = 0, 0 = 2x - 1, so x = 1/2. Plot the point (1/2, 0).- Draw the line: Connect the two points with a dashed line. We use a dashed line because the inequality is "less than" (<), meaning the points on the line itself are not included in the solution.- Shading the solution area: Since y is "less than" 2x - 1, shade the area below the line. You can test a point (like (0,0)) to confirm the shading. If 0 < 2(0) - 1 (which is false), then shade the area not containing (0,0). 2. Graphing y ≤ x + 3 - Treat it as an equation: Graph the line y = x + 3. - Find the y-intercept: When x = 0, y = 3. Plot the point (0, 3).- Find the x-intercept: When y = 0, 0 = x + 3, so x = -3. Plot the point (-3, 0).- Draw the line: Connect the two points with a solid line. We use a solid line because the inequality is "less than or equal to" (≤), meaning the points on the line are included in the solution.- Shading the solution area: Since y is "less than or equal to" x + 3, shade the area below the line. Again, you can test a point (like (0,0)) to confirm. 0 ≤ 0 + 3 (which is true), so shade the area containing (0,0).

Answered by ocbinayoriivan | 2024-10-17