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In Math / Junior High School | 2024-10-17

pasagot naman po math problem thank you ​

Asked by abcdefgiz09129

Answer (1)

Answer: number 1 You're asking to find the values of y for the given function y = (x + 1)(x - 2)(x - 3) when x takes on the values -4, -2, 0, 4, and 5. Let's calculate each value step-by-step: When x = -4 1. Substitute x = -4:y = (-4 + 1)(-4 - 2)(-4 - 3)2. Simplify:y = (-3)(-6)(-7)3. Calculate:y = -126 When x = -2 1. Substitute x = -2:y = (-2 + 1)(-2 - 2)(-2 - 3)2. Simplify:y = (-1)(-4)(-5)3. Calculate:y = -20 When x = 0 1. Substitute x = 0:y = (0 + 1)(0 - 2)(0 - 3)2. Simplify:y = (1)(-2)(-3)3. Calculate:y = 6 When x = 4 1. Substitute x = 4:y = (4 + 1)(4 - 2)(4 - 3)2. Simplify:y = (5)(2)(1)3. Calculate:y = 10 When x = 5 1. Substitute x = 5:y = (5 + 1)(5 - 2)(5 - 3)2. Simplify:y = (6)(3)(2)3. Calculate:y = 36 Therefore, the values of y for the given function are: - y = -126 when x = -4- y = -20 when x = -2- y = 6 when x = 0- y = 10 when x = 4- y = 36 when x = 5

Answered by ocbinayoriivan | 2024-10-17