SOLUTION:Step 1: List the given values.[tex]\begin{aligned} & W = \text{200 J} \\ & t = \text{5 min} \times \frac{\text{60 s}}{\text{1 min}} = \text{300 s} \end{aligned}[/tex]Step 2: Calculate the power[tex]\begin{aligned} P & = \frac{W}{t} \\ & = \frac{\text{200 J}}{\text{300 s}} \\ & = \boxed{\text{0.667 W}} \end{aligned}[/tex]Hence, the power rating of the bulb is 0.667 W.