Answer:Therefore, the sum of all numbers from 1 to 4000 is 8001000.
Step-by-step explanation:To find the sum of the numbers from 1 to 4000, you can use the formula for the sum of the first n natural numbers:[ S = \frac{n(n + 1)}{2} ]where n = 4000.Plugging in the value of n:[ S = \frac{4000 \times (4000 + 1)}{2} = \frac{4000 \times 4001}{2} = \frac{16,004,000}{2} = 8,002,000 ]So, the sum of the numbers from 1 to 4000 is 8,002,000.