Computes the perimeter of different geometric shapes in everyday life, e.g.: LS3MP-"Perimeter of Geometrical Shapes"Post-Test:AE Level:Direction: Solve the following problems.tt1. There are two lots for sale. Lot A is 18 meters long and 12 meterswide while Lot B is 19 meters long and 11 meters wide. Which lotwill require a longer barbed wire to fence it?2. How many meters of rope will Jimmy need to enclose a play areafor children that is 12 meters long and 10 meters wide?3. A barangay health center is 9 meters long and 7 meters wide. Whatis its perimeter?
Answer (1)
Answer:Let's solve each problem step-by-step using the formula for the perimeter of a rectangle:\[ \text{Perimeter} = 2 \times (\text{Length} + \text{Width}) \]1. **Lot A and Lot B Comparison:** - **Lot A:** - Length = 18 meters - Width = 12 meters - Perimeter of Lot A: \[ \text{Perimeter} = 2 \times (18 + 12) = 2 \times 30 = 60 \text{ meters} \] - **Lot B:** - Length = 19 meters - Width = 11 meters - Perimeter of Lot B: \[ \text{Perimeter} = 2 \times (19 + 11) = 2 \times 30 = 60 \text{ meters} \] Both Lot A and Lot B have the same perimeter of **60 meters**. Therefore, both lots require the same amount of barbed wire.2. **Play Area Enclosure:** - Length = 12 meters - Width = 10 meters - Perimeter of the play area: \[ \text{Perimeter} = 2 \times (12 + 10) = 2 \times 22 = 44 \text{ meters} \] Jimmy will need **44 meters** of rope to enclose the play area.3. **Barangay Health Center:** - Length = 9 meters - Width = 7 meters - Perimeter of the health center: \[ \text{Perimeter} = 2 \times (9 + 7) = 2 \times 16 = 32 \text{ meters} \] The perimeter of the barangay health center is **32 meters**.
