3x³+6x²+9+ -18use synthetic division​

Answer:Let's use synthetic division to divide the polynomial 3x³ + 6x² + 9x - 18 by (x + 2). 1. Set up the Synthetic Division: - Write the coefficients of the polynomial in a row: 3 6 9 -18- Since we're dividing by (x + 2), use the opposite of the constant term, which is -2. plaintext
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-2 | 3 6 9 -18 -----------------  2. Perform the Synthetic Division: - Bring down the first coefficient (3).- Multiply the number you brought down (3) by the divisor (-2) and write the result ( -6) below the next coefficient (6).- Add the numbers in the second column (6 + -6 = 0).- Repeat the process for the remaining coefficients. plaintext
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-2 | 3 6 9 -18 -6 0 -18 ----------------- 3 0 9 0  3. Interpret the Results: - The numbers in the bottom row represent the coefficients of the quotient polynomial, starting with the constant term.- The last number (0) is the remainder. Therefore, the result of the synthetic division is: - Quotient: 3x² + 9- Remainder: 0 This means: 3x³ + 6x² + 9x - 18 = (x + 2)(3x² + 9)

Answered by angeldenaga1 | 2024-09-10