Aspirin is made by the reaction of salicylic acid with acetic anhydride. How many grams of aspirin are produced if 85.0 g of salicylic acid is treated with excess acetic anhydride
Answer (1)
Answer: * Write the balanced chemical equation: C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + C₂H₄O₂ This equation shows that one mole of salicylic acid reacts with one mole of acetic anhydride to produce one mole of aspirin and one mole of acetic acid. * Calculate the moles of salicylic acid: Molar mass of salicylic acid (C₇H₆O₃) = 138.12 g/mol Moles of salicylic acid = 85.0 g / 138.12 g/mol = 0.615 mol * Determine the moles of aspirin produced: From the balanced equation, we see that 1 mole of salicylic acid produces 1 mole of aspirin. Therefore, 0.615 mol of salicylic acid will produce 0.615 mol of aspirin. * Calculate the mass of aspirin produced: Molar mass of aspirin (C₉H₈O₄) = 180.16 g/mol Mass of aspirin = 0.615 mol * 180.16 g/mol = 110.8 gTherefore, 85.0 g of salicylic acid will produce 110.8 g of aspirin
