Insert a geometric mean between k and 1/k.
Answer (1)
SOLUTION:Based on the problem, the geometric sequence formed isk, a₂, 1/kSolving for a₂ by using the concept of the common ratio of geometric sequence[tex]\begin{aligned} \frac{a_2}{k} & = \frac{1/k}{a_2} \\ a_2^2 & = k(1/k) \\ a_2^2 & = 1 \\ \sqrt{a_2^2} & = \sqrt{1} \\ a_2 & = \boxed{1} \end{aligned}[/tex]Hence, the geometric mean between k and 1/k is 1.
