how to balance chemical equation CaCO3+ H3PO4 -> Ca3(PO4)+ CO2+ H2O
Answer (1)
3CaCO 3 +2H 3 PO 4 →Ca 3 (PO 4 ) 2 +3CO 2 +6H 2 O1 Write the unbalanced equation clearly:CaCO3+H3PO4→Ca3(PO4)+CO2+H2OCaCO 3 +H 3 PO 4 →Ca 3 (PO 4 )+CO 2 +H 2 O2 Identify the number of each type of atom on both sides of the equation.Reactants:Ca: 1 (from CaCO3)C: 1 (from CaCO3)O: 3 (from CaCO3) + 4 (from H3PO4) = 7H: 3 (from H3PO4)P: 1 (from H3PO4)Products:Ca: 3 (from Ca3(PO4)2)C: 1 (from CO2)O: 8 (from Ca3(PO4)2) + 2 (from CO2) + 1 (from H2O) = 11H: 2 (from H2O)P: 2 (from Ca3(PO4)2)3 Balance the calcium (Ca) atoms. Since there are 3 Ca in the products, we need 3 CaCO3 in the reactants:3CaCO3+H3PO4→Ca3(PO4)+CO2+H2O3CaCO 3 +H 3 PO 4 →Ca 3 (PO 4 )+CO 2 +H 2 O4 Now balance the phosphorus (P) atoms. We have 2 P in the product (from Ca3(PO4)2), so we need 2 H3PO4:3CaCO3+2H3PO4→Ca3(PO4)+CO2+H2O3CaCO 3 +2H 3 PO 4 →Ca 3 (PO 4 )+CO 2 +H 2 O5 Now let's balance the carbon (C) atoms. We have 3 CaCO3 providing 3 C, so we need 3 CO2:3CaCO3+2H3PO4→Ca3(PO4)+3CO2+H2O3CaCO 3 +2H 3 PO 4 →Ca 3 (PO 4 )+3CO 2 +H 2 O6 Finally, balance the hydrogen (H) and oxygen (O) atoms. We have 6 H from 2 H3PO4, and we can achieve this by having 6 H2O:3CaCO3+2H3PO4→Ca3(PO4)+3CO2+6H2O3CaCO 3 +2H 3 PO 4 →Ca 3 (PO 4 )+3CO 2 +6H 2 O7 Check all atoms to ensure they are balanced:Ca: 3 (reactants) = 3 (products)C: 3 (reactants) = 3 (products)O: 9 (from 3 CaCO3) + 8 (from 2 H3PO4) = 17 (reactants) and 12 (from Ca3(PO4)2) + 6 (from 3 CO2) + 6 (from 6 H2O) = 24 (products)H: 6 (reactants) = 6 (products)P: 2 (reactants) = 2 (products)Final balanced equation:3CaCO3+2H3PO4→Ca3(PO4)2+3CO2+6H2O3CaCO 3 +2H 3 PO 4 →Ca 3 (PO 4 ) 2 +3CO 2 +6H 2 O
