What is Flex ATX Answer ​

Answer:1) x²+18781√√XX√81=9=Cx+9)(x+9)=(x+9)222₁\ x²+6x+9√x²=x√9 = 3J = (x+3)(x+3)(x+3)2x ^ 2 - 6x - 16 > 0Y²+5×+60x ^ 2 - 6x - 16 > 0P(x)=²¹+3÷1) x²+18781√√XX√81=9=Cx+9)(x+9)=(x+9)222₁\ x²+6x+9√x²=x√9 = 3J = (x+3)(x+3)(x+3)2

Answered by zenesperida | 2024-09-09