gen math[tex] {4}^{3x + 2} < 64[/tex]solving exponential inequality ​

Answer:tol di ko pa to sure, di pa namin nadidiscuss haha intindihin mo na langStep-by-step explanation:4^3x+2 < 4^33x + 2 < 33x - 1 < 03x - 1 = 0x = ⅓<-------o-------->-inf ⅓ infinterval (-inf,⅓)test pt 04^3(0) + 2 < 4^34^2 < 4^3trueinterval (⅓,inf)test pt 14^3(1)+2 < 4^34^5 < 4^3falsesolution set in interval notation (-inf, ⅓)

Answered by haylowds | 2024-09-09