4x²-8x-5 Quadratic factored​

Answer:Here's how to factor the quadratic equation 4x² - 8x - 5 = 0: 1. Find two numbers that multiply to give (4)(-5) = -20 and add up to -8. - The numbers -10 and 2 satisfy these conditions:- -10 * 2 = -20- -10 + 2 = -8 2. Rewrite the middle term (-8x) using the two numbers you found. - 4x² - 10x + 2x - 5 = 0 3. Factor by grouping. - Group the first two terms and the last two terms:- (4x² - 10x) + (2x - 5) = 0- Factor out the greatest common factor from each group:- 2x(2x - 5) + 1(2x - 5) = 0- Notice that both groups now share a common factor (2x - 5):- (2x - 5)(2x + 1) = 0 4. Set each factor equal to zero and solve for x. - 2x - 5 = 0 - 2x = 5- x = 5/2- 2x + 1 = 0 - 2x = -1- x = -1/2 The factored form of the equation is (2x - 5)(2x + 1) = 0, and the solutions are x = 5/2 and x = -1/2.

Answered by deveramichael753 | 2024-09-09