In Science / Junior High School | 2024-09-08
Asked by jacobandreilansangan
KE = [tex]\frac{1}{2}mv^{2} \\[/tex]KE = 58.1m = 0.230[tex]58.1 = \frac{1}{2}(0.230)v^{2} \\[/tex][tex]v^2= \frac{58.1*2}{0.230} \\\\v=\sqrt{\frac{58.1*2}{0.230}}\\v = 22.4770 m/s[/tex]
Answered by strugglingseia77122 | 2024-09-08