Sample Problem
A ball is thrown straight downward with a speed of 0.50 m/s from a height of 4.0 meters. What is the speed of the ball 0.7 seconds after it is released?
Answer (1)
Answer:Here's how to solve this problem using the principles of kinematics: Understanding the Problem - Initial Velocity (v₀): -0.50 m/s (negative since it's thrown downward)- Initial Height (y₀): 4.0 m- Time (t): 0.7 s- Acceleration due to gravity (g): 9.8 m/s² (always acts downward)- Final Velocity (v): What we need to find Using the Kinematic Equation We can use the following kinematic equation to solve for the final velocity: v = v₀ + at Where: - v = final velocity- v₀ = initial velocity- a = acceleration- t = time Plugging in the Values v = -0.50 m/s + (9.8 m/s²)(0.7 s) Calculating the Final Velocity v = -0.50 m/s + 6.86 m/sv = 6.36 m/s Answer The speed of the ball 0.7 seconds after it is released is 6.36 m/s.Hope it helps, brainliests me pls
