10x2-2x=8 complete the square

Answer:1. Move the constant term to the right side: 10x² - 2x = 810x² - 2x - 8 = 0 2. Divide both sides by the coefficient of the x² term (which is 10): x² - (2/10)x - 8/10 = 0x² - (1/5)x - 4/5 = 0 3. Take half of the coefficient of the x term, square it, and add it to both sides: Half of -(1/5) is -(1/10). Squaring this gives (1/100). x² - (1/5)x + (1/100) - 4/5 = (1/100) 4. Factor the left side as a perfect square trinomial: (x - 1/10)² - 4/5 = 1/100 5. Isolate the squared term: (x - 1/10)² = 1/100 + 4/5(x - 1/10)² = 81/100 6. Take the square root of both sides: x - 1/10 = ±√(81/100)x - 1/10 = ±9/10 7. Solve for x: x = 1/10 ± 9/10 Therefore, the solutions are:x = 1 or x = -8/10 = -4/5

Answered by girlzamba05 | 2024-09-08