transforme each the following equation to a quadratic equation in the form ax²+bx+c=0[tex] 1. x(x + 3 = 28[/tex]formula
Answer (1)
Answer:x^2+3x-28Step-by-step explanation:x(x+3)=x^2+3xtranspose 28 and it wil become negativesox^2+3x-28=0
Answer:x^2+3x-28Step-by-step explanation:x(x+3)=x^2+3xtranspose 28 and it wil become negativesox^2+3x-28=0
