In Math / Senior High School | 2024-09-08
Asked by edenrotilla388
SOLUTION:(x - 3)² = 12(y - 2)x² - 2(3)(x) + 3² = 12y - 12(2)x² - 6x + 9 = 12y - 24x² - 6x - 12y + 9 + 24 = 0x² - 6x - 12y + 33 = 0
Answered by GreatRedSpot | 2024-09-08