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In Math / Junior High School | 2024-09-07

Solving Quadratic Equation by completing the square 1.x²-2x=32.x²+4x-21=03.x²+10x+9=0​

Asked by marvinsigua1980

Answer (1)

Step-by-step explanation:1. x² - 2x = 3 - Step 1: x² - 2x = 3- Step 2: Half of -2 is -1, and (-1)² = 1. Add 1 to both sides:x² - 2x + 1 = 3 + 1- Step 3: Factor the left side: (x - 1)² = 4- Step 4: Take the square root of both sides: x - 1 = ±2- Step 5: Solve for x:- x - 1 = 2 => x = 3- x - 1 = -2 => x = -1 2. x² + 4x - 21 = 0 - Step 1: x² + 4x = 21- Step 2: Half of 4 is 2, and 2² = 4. Add 4 to both sides:x² + 4x + 4 = 21 + 4- Step 3: Factor the left side: (x + 2)² = 25- Step 4: Take the square root of both sides: x + 2 = ±5- Step 5: Solve for x:- x + 2 = 5 => x = 3- x + 2 = -5 => x = -7 3. x² + 10x + 9 = 0 - Step 1: x² + 10x = -9- Step 2: Half of 10 is 5, and 5² = 25. Add 25 to both sides:x² + 10x + 25 = -9 + 25- Step 3: Factor the left side: (x + 5)² = 16- Step 4: Take the square root of both sides: x + 5 = ±4- Step 5: Solve for x:- x + 5 = 4 => x = -1- x + 5 = -4 => x = -9

Answered by aikaluv67 | 2024-09-07