f(x) = x ^ 2 + 6x + 9 R(x) = x ^ 2 g(x) = x ^ 2 - 4 1. (R*\mathbb{C})(x) C(x) = 1/x T(x) = sqrt(x - 2) h(x) = 3x + 5 (k + C)(- 1/a) 2 (h g) (x) 7. (CT)(10) (h + f)(x) 8. (TF)(- 1) > 4 ( T' * C(x) 9. (RT)(2) 5. (gf)(x) 10(fh)(- 1/2)

Question

f(x) = x ^ 2 + 6x + 9 R(x) = x ^ 2 g(x) = x ^ 2 - 4 1. (R*\mathbb{C})(x) C(x) = 1/x T(x) = sqrt(x - 2) h(x) = 3x + 5 (k + C)(- 1/a) 2 (h g) (x) 7. (CT)(10) (h + f)(x) 8. (TF)(- 1) &gt; 4 ( T' * C(x) 9. (RT)(2) 5. (gf)(x) 10(fh)(- 1/2)

rheymaulio8 · Answer

adding and subtracting fractions with unlike denominators

f(x) = x ^ 2 + 6x + 9 R(x) = x ^ 2 g(x) = x ^ 2 - 4 1. (R\mathbb{C})(x) C(x) = 1/x T(x) = sqrt(x - 2) h(x) = 3x + 5 (k + C)(- 1/a) 2 (h g) (x) 7. (CT)(10) (h + f)(x) 8. (TF)(- 1) > 4 ( T' C(x) 9. (RT)(2) 5. (gf)(x) 10(fh)(- 1/2)

Answer (1)

f(x) = x ^ 2 + 6x + 9 R(x) = x ^ 2 g(x) = x ^ 2 - 4 1. (R*\mathbb{C})(x) C(x) = 1/x T(x) = sqrt(x - 2) h(x) = 3x + 5 (k + C)(- 1/a) 2 (h g) (x) 7. (CT)(10) (h + f)(x) 8. (TF)(- 1) &gt; 4 ( T' * C(x) 9. (RT)(2) 5. (gf)(x) 10(fh)(- 1/2)

Answer (1)

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f(x) = x ^ 2 + 6x + 9 R(x) = x ^ 2 g(x) = x ^ 2 - 4 1. (R\mathbb{C})(x) C(x) = 1/x T(x) = sqrt(x - 2) h(x) = 3x + 5 (k + C)(- 1/a) 2 (h g) (x) 7. (CT)(10) (h + f)(x) 8. (TF)(- 1) > 4 ( T' C(x) 9. (RT)(2) 5. (gf)(x) 10(fh)(- 1/2)

[Sagot para sa’yo] during this quarter which math lesson is difficult? explain why?