4. Complete the table with the correct information.Compound1. GlucoseChemicalFormulaMolar MassPercentagecompositionCHO.2. PropaneCaHa3. Hydrogen peroxideH2O24. Copper sulfateCuSOshow your solution ​

Answer:Compound Chemical Formula Molar Mass (g/mol) Percentage Composition 1. Glucose C6H12O6 180.16 C: 40.00%, H: 6.71%, O: 53.29% 2. Propane C3H8 44.10 C: 81.71%, H: 18.29% 3. Hydrogen peroxide H2O2 34.02 H: 5.88%, O: 94.12% 4. Copper sulfate CuSO4 159.61 Cu: 39.81%, S: 20.04%, O: 40.15% Solutions: 1. Glucose (C6H12O6) - Molar Mass:- C: 6 atoms * 12.01 g/mol = 72.06 g/mol- H: 12 atoms * 1.01 g/mol = 12.12 g/mol- O: 6 atoms * 16.00 g/mol = 96.00 g/mol- Total Molar Mass: 72.06 + 12.12 + 96.00 = 180.16 g/mol- Percentage Composition:- C: (72.06 g/mol / 180.16 g/mol) * 100% = 40.00%- H: (12.12 g/mol / 180.16 g/mol) * 100% = 6.71%- O: (96.00 g/mol / 180.16 g/mol) * 100% = 53.29% 2. Propane (C3H8) - Molar Mass:- C: 3 atoms * 12.01 g/mol = 36.03 g/mol- H: 8 atoms * 1.01 g/mol = 8.08 g/mol- Total Molar Mass: 36.03 + 8.08 = 44.10 g/mol- Percentage Composition:- C: (36.03 g/mol / 44.10 g/mol) * 100% = 81.71%- H: (8.08 g/mol / 44.10 g/mol) * 100% = 18.29% 3. Hydrogen peroxide (H2O2) - Molar Mass:- H: 2 atoms * 1.01 g/mol = 2.02 g/mol- O: 2 atoms * 16.00 g/mol = 32.00 g/mol- Total Molar Mass: 2.02 + 32.00 = 34.02 g/mol- Percentage Composition:- H: (2.02 g/mol / 34.02 g/mol) * 100% = 5.88%- O: (32.00 g/mol / 34.02 g/mol) * 100% = 94.12% 4. Copper sulfate (CuSO4) - Molar Mass:- Cu: 1 atom * 63.55 g/mol = 63.55 g/mol- S: 1 atom * 32.07 g/mol = 32.07 g/mol- O: 4 atoms * 16.00 g/mol = 64.00 g/mol- Total Molar Mass: 63.55 + 32.07 + 64.00 = 159.61 g/mol- Percentage Composition:- Cu: (63.55 g/mol / 159.61 g/mol) * 100% = 39.81%- S: (32.07 g/mol / 159.61 g/mol) * 100% = 20.04%- O: (64.00 g/mol / 159.61 g/mol) * 100% = 40.15%

Answered by lxynkeiko | 2024-09-05